This question was previously asked in

SSC CGL Tier 2 Quant Previous Paper 5 (Held On: 12 September 2019)

- 54°
- 67°
- 71°
- 63°

Option 4 : 63°

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**Short Trick****∶**

As we know,

∠A + ∠B = 2∠CED

⇒ 49° + ∠B = 2 × 56°

⇒ ∠B = 112° – 49° = 63°

**Detailed Solution****∶**

In ΔCED

∠C/2 + ∠D/2 + ∠CED = 180°

⇒ ∠C/2 + ∠D/2 + 56° = 180°

⇒ ∠C/2 + ∠D/2 = 180° – 56° = 124°

⇒ ∠C + ∠D = 124° × 2 = 248°

As we know,

∠A + ∠B + ∠C + ∠D = 360°

⇒ 49° + ∠B + 248° = 360°

⇒ ∠B = 360° – 297° = 63°

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